CLASS 7 MATH Question Paper Set 3 – Higher Complexity – TOPICS: A Tale of three intersecting lines, Arithmetic Expressions, Expressions using letter numbers.

🔥 SET 3 (Higher Complexity)

TOPICS: A Tale of three intersecting lines, Arithmetic Expressions, Expressions using letter numbers.

SECTION – A

  1. Which cannot be third side if two sides are 12 cm and 7 cm?
    (a) 18 cm
    (b) 5 cm
    (c) 10 cm
    (d) 17 cm
  2. If p and q are twin primes and pq = 899, find p + q.
  3. What must be subtracted from (7x² – 3x + 4) to get (2x² + x – 6)?
  4. The cost of x pens is ₹(5x + 20). Write algebraic expression for cost of (x + 3) pens.
  5. If a and b are consecutive primes greater than 3, then a + b is always:
    (a) even
    (b) odd
    (c) prime
    (d) multiple of 3
  6. Assertion–Reason
    Assertion: If exterior angle of triangle is 120° and two opposite interior angles are equal, each is 60°.
    Reason: Exterior angle equals sum of opposite interior angles.

SECTION – B

  1. Simplify:

(i) 50 – 10 × 4 + 6 × 3 – 8

(ii) 5x – 3y(4 – 6) + (2x – y) – (3x + 2y)


  1. Contributions:

A: 4(2m + n – p) – 3(m – 2n + p)
B: 3(m + 2n – 3p) – 2(2m – n + p)
C: 5(m – n + 2p) – (3m + 2n – p)

a) Total
b) Compare with target (20m + 15n – 18p)


  1. Perimeter of triangle (3x + 1), (2x + 5), (x + 7) equals twice perimeter of square side (x + 2). Find x.

  1. In isosceles triangle, vertex angle is 5 times base angle. Find angles.

  1. Construct triangle using ASA:
    AB = 7 cm, ∠ BAC = 35°, ∠ ABC = 85°

SECTION – C

  1. Case Study

Rohan selects strips 4 cm, 6 cm, 11 cm.

(a) Can triangle form?
(b) State inequality property.
(c) Find all possible integer values of third side if other sides are 5 cm and 9 cm.

SECTION – A

  1. (a) 18 cm
  2. Twin primes: 29 and 31
    p + q = 60
  3. 5x² – 4x + 10
  4. 5(x + 3) + 20 = 5x + 35
  5. (a) even
  6. (a) Both true, correct explanation

SECTION – B

7.

(i) 50 – 40 + 18 – 8 = 20

(ii) 5x – 3y(-2) + 2x – y – 3x – 2y
= 5x + 6y + 2x – y – 3x – 2y
= 4x + 3y


  1. Total = (6m + 15n – 10p)

Target = (20m + 15n – 18p)

Shortage = (14m – 8p)


  1. x = 5

  1. Base angle = 15°
    Vertex angle = 75°

  1. Construction steps same ASA method

(a) No (4 + 6 = 10 < 11)

(b) Triangle inequality theorem

(c) Third side range:
|9 – 5| < x < 14
4 < x < 14

Possible integers: 5 to 13

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