🔥 SET 3 (Higher Complexity)
TOPICS: A Tale of three intersecting lines, Arithmetic Expressions, Expressions using letter numbers.
SECTION – A
- Which cannot be third side if two sides are 12 cm and 7 cm?
(a) 18 cm
(b) 5 cm
(c) 10 cm
(d) 17 cm - If p and q are twin primes and pq = 899, find p + q.
- What must be subtracted from (7x² – 3x + 4) to get (2x² + x – 6)?
- The cost of x pens is ₹(5x + 20). Write algebraic expression for cost of (x + 3) pens.
- If a and b are consecutive primes greater than 3, then a + b is always:
(a) even
(b) odd
(c) prime
(d) multiple of 3 - Assertion–Reason
Assertion: If exterior angle of triangle is 120° and two opposite interior angles are equal, each is 60°.
Reason: Exterior angle equals sum of opposite interior angles.
SECTION – B
- Simplify:
(i) 50 – 10 × 4 + 6 × 3 – 8
(ii) 5x – 3y(4 – 6) + (2x – y) – (3x + 2y)
- Contributions:
A: 4(2m + n – p) – 3(m – 2n + p)
B: 3(m + 2n – 3p) – 2(2m – n + p)
C: 5(m – n + 2p) – (3m + 2n – p)
a) Total
b) Compare with target (20m + 15n – 18p)
- Perimeter of triangle (3x + 1), (2x + 5), (x + 7) equals twice perimeter of square side (x + 2). Find x.
- In isosceles triangle, vertex angle is 5 times base angle. Find angles.
- Construct triangle using ASA:
AB = 7 cm, ∠ BAC = 35°, ∠ ABC = 85°
SECTION – C
- Case Study
Rohan selects strips 4 cm, 6 cm, 11 cm.
(a) Can triangle form?
(b) State inequality property.
(c) Find all possible integer values of third side if other sides are 5 cm and 9 cm.
SECTION – A
- (a) 18 cm
- Twin primes: 29 and 31
p + q = 60 - 5x² – 4x + 10
- 5(x + 3) + 20 = 5x + 35
- (a) even
- (a) Both true, correct explanation
SECTION – B
7.
(i) 50 – 40 + 18 – 8 = 20
(ii) 5x – 3y(-2) + 2x – y – 3x – 2y
= 5x + 6y + 2x – y – 3x – 2y
= 4x + 3y
- Total = (6m + 15n – 10p)
Target = (20m + 15n – 18p)
Shortage = (14m – 8p)
- x = 5
- Base angle = 15°
Vertex angle = 75°
- Construction steps same ASA method
(a) No (4 + 6 = 10 < 11)
(b) Triangle inequality theorem
(c) Third side range:
|9 – 5| < x < 14
4 < x < 14
Possible integers: 5 to 13
