1. The value of 25 – 5 × 3 + 2 is?
(a) 12 (b) 10 (c) 30 (d) 15
Answer: (a) 12
2. Which expression is NOT equal to 5 × 8?
(a) (10 – 5) × 8
(b) 5 × (4 + 4)
(c) 5 × 10 – 5 × 2
(d) (5 × 4) + 2
Answer: (d)
3. If 40 + (x + 5) = 40 + 12, find x.
Answer: 7
4. 200 – (30 – 10) equals?
Answer: 200 – 30 + 10
5. Which is smaller: 75 × 15 or 75 × 10?
Answer: 75 × 10
6. Terms of 10 ÷ 2 + 5 × 3 – 6 are?
Answer: 10 ÷ 2, 5 × 3, -6
7. Which is equal to 54 + 12 × 3 – 6?
Answer: 54 + (12 × 3) – 6
8. Expression for “sum of 10 and y divided by 2”?
Answer: (10 + y) ÷ 2
In the following questions 9 and 10, a statement of assertion (A) is followed by a statement of
reason (R). Mark the correct choice as:
(a) Both assertion (A) and reason (R) are true and reason (R) is the correct explanation of assertion (A).
(b) Both assertion (A) and reason (R) are true but reason (R) is not the correct explanation of assertion (A).
(c) Assertion (A) is true but reason (R) is false.
(d) Assertion (A) is false but reason (R) is true.
9. Assertion (A): The value of the expression 8 + 4 ÷ 2 is 6.
Reason (R): Division is performed before addition according to the order of operations.
Ans. 8 + 4 ÷ 2 = 8 + 2 = 10. Assertion A is false and R is true.
So the correct option is (d).
10. Assertion (A): The expression 50 × (10 – 2) is equal to 50 × 10 – 50 × 2.
Reason (R): This is an example of the associative property of multiplication.
Ans. The assertion is true, this is a correct application of the distributive property. However, the
reason states it is the associative property, which is false. Therefore, A is true, but R is false.
18. For Annual Day, the school orders:
120 chairs at ₹150 each
6 loudspeakers at ₹2500 each
15 decorative lights at ₹320 each
(a) Form an expression for total cost.
(b) Find total cost.
(c) If ₹40,000 was budgeted, find the remaining amount or shortage
Ans. Chairs: 120 at ₹150 each → 120 × 150
Loudspeakers: 6 at ₹2500 each → 6 × 2500
Decorative lights: 15 at ₹320 each → 15 × 320
(a) Total = (120 × 150) + (6 × 2500) + (15 × 320)
(b) Total cost
120 × 150 = 18, 6 × 2500 = 15, 15 × 320 = 4,800
Total = 18,000 + 15,000 + 4,800 = ₹37,800
(c) Remaining amount or shortage (Budget = ₹40,000)
Remaining = 40,000 − 37,800 = ₹2,200 remaining (no shortage)
Section E – Case Study
19. Meera, with her birthday approaching, was buzzing with excitement as she planned her party. She
wanted to make it special for all her friends. With a budget in mind, she visited a local store to buy
everything she needed. She carefully picked out six gift items for the party guests, each costing
₹35. Next, she selected five packets of colorful balloons, with each packet priced at ₹18. The
most important part, the birthday cake, was a beautiful creation that cost ₹250. With all her
purchases in hand, she headed home to prepare for the celebration.
(a) Write an arithmetic expression for the total cost
(b) Find total expenditure
(c) If she had ₹600, how much is left?
(d) If she adds 2 return gifts at ₹30 each, what will be the new total?
Ans. Gift items: 6 at ₹35 each → 6 × 35
Balloon packets: 5 at ₹18 each → 5×18
Cake: 1 at ₹250 → 250
(a) Arithmetic expression for total cost: Total = (6 × 35) + (5 × 18) + 250
(b) Total expenditure
6 × 35 = 210, 5 × 18 = 90
Total = 210 + 90 + 250 = ₹550
(c) Leftover = 600 – 550 = ₹50
(d) Extra for return gifts = 2 × 30 = 60
New total = 550 + 60 = ₹610
20. Case Study 2: Water Bill Calculation
Every month, the family braced for the dreaded utility bill. This
month, they were particularly careful with their water usage,
knowing each unit was priced at ₹7. Despite their best efforts, the
bill showed they had consumed 30 units of water. Along with
their standard ₹250 maintenance charge, a small oversight
meant a ₹50 late fine was added to their total, turning a simple
bill into a frustrating calculation of their monthly household
expenses.
(a) Write a numerical expression for the total water bill
(b) Calculate total
(c) If the household paid ₹600, find the balance
(d) What would be the bill if they used 40 units instead?
Maintenance charges: ₹250
Late fine: ₹50
(a) Expression for total bill
Total bill = (30 × 7) + 250 + 50
(b) 30 × 7 = 210
210 + 250 + 50 = 510
Total bill = ₹510
(c) 600 – 510 = 90
Balance (change to return) = ₹90
(d) Bill if 40 units were used instead
(40 × 7) + 250 + 50 = 280 + 250 + 50 = 580
New bill = ₹580
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