Class 7 – DECIMALS PRACTICE WORKSHEET – SET 2

📘 Class 7 – DECIMALS PRACTICE WORKSHEET – SET 2

Subject: Mathematics
Grade: VII


I. Choose the correct option.

  1. The decimal value of 932 divided by 10,000 is
    (a) 0.0932
    (b) 9.32
    (c) 0.932
    (d) 0.00932
  2. Product of 0.9 and 0.05 is
    (a) Greater than 0.9
    (b) Less than both numbers
    (c) Equal to 1
    (d) Greater than both numbers
  3. If 35 × 18 = 630, then 0.35 × 0.18 is
    (a) 0.63
    (b) 6.3
    (c) 0.0063
    (d) 0.063
  4. A bus travels 1.875 km daily. In 8 days, it travels
    (a) 15 km
    (b) 1.5 km
    (c) 150 km
    (d) 0.15 km
  5. 576 divided by 12 equals
    (a) 4.8
    (b) 48
    (c) 0.48
    (d) 480

II. Solve the following.

  1. A machine produces 0.48 kg of rice per minute. How much rice will it produce in 25 minutes? State whether the product is greater or smaller than both numbers.
  2. Convert into kilograms and find total price at ₹ 220 per kg:
    Cashews – 200 g
    Walnuts – 350 g
    Dates – 150 g
  3. A swimmer swims 5.8 laps of a pool, each lap measuring 0.85 km.
    (a) Find total distance.
    (b) Compare product with both numbers.
    (c) Give reason.
  4. Rohit buys 5 litres of diesel and 2 litres of oil.
    Diesel costs ₹ 91.85 per litre and oil costs ₹ 135.60 per litre.
    Find total amount spent.
  5. The product of two decimals is 4.68. If one number is 12, find the other number.
  6. Find area of rectangle whose length is 9.4 m and breadth is 2.8 m.
  7. Each side of a regular polygon is 4.2 cm. If its perimeter is 33.6 cm, find number of sides.

III. Case Study-Based Questions

  1. A gym trainer calculates daily calorie burn using formula:

Calories burned = 0.65 × body weight (kg)

(a) If Rohan weighs 72 kg, find calories burned daily.

(b) If a person burns 39 calories daily, find his body weight.

(c) Gym membership costs ₹ 1250.75 per month. Find cost for 3 months.

(d) If ₹ 4000 is paid, how much money will be returned?

(e) Find cost for 8 months.

✅ ANSWER KEY – SET 2

I. Choose the correct option

  1. (a) 0.0932
  2. (b) Less than both numbers
  3. (d) 0.063
  4. (a) 15 km
  5. (b) 48

II. Solve the following

0.48 × 25 = 12 kg
Product is greater than both numbers (25 > 1, so product increases).


200 g = 0.2 kg
350 g = 0.35 kg
150 g = 0.15 kg

Total weight = 0.2 + 0.35 + 0.15 = 0.7 kg
Total cost = 0.7 × 220 = ₹154


(a) 5.8 × 0.85 = 4.93 km
(b) 4.93 is less than 5.8 but greater than 0.85
(c) One number is greater than 1 and the other is less than 1, so product lies between them.


Diesel = 5 × 91.85 = ₹459.25
Oil = 2 × 135.60 = ₹271.20

Total = 459.25 + 271.20 = ₹730.45


4.68 ÷ 12 = 0.39


Area = 9.4 × 2.8 = 26.32 sq. m


Number of sides = 33.6 ÷ 4.2 = 8 sides


III. Case Study

(a) 0.65 × 72 = 46.8 calories

(b) 39 ÷ 0.65 = 60 kg

(c) 1250.75 × 3 = ₹3752.25

(d) 4000 − 3752.25 = ₹247.75

(e) 1250.75 × 8 = ₹10006.00

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