📘 CLASS 7 – MATH QUESTION PAPER – SET 2
ANNUAL EXAMINATION (2025–2026)
SUBJECT: MATHEMATICS
TOPICS:
Ch.2 Arithmetic Expressions
Ch.4 Expressions using Letter-Numbers
Ch.6 Number Play
Ch.7 A Tale of Three Intersecting lines
Part 2:
Ch.1 Geometric Twins
Ch.2 Operations with Integers
Ch.4 Another Peek Beyond the Point
SECTION – A
I. Choose the correct option:
- Two sides of a triangle are 12 cm and 8 cm. Which of the following cannot be the third side?
(a) 7 cm
(b) 5 cm
(c) 21 cm
(d) 10 cm
- If p and q are twin primes and p + q = 18, find the value of pq.
(a) 63
(b) 80
(c) 48
(d) 35
- What should be added to (4y² – 3y + 2) to get (7y² + y – 5)?
(a) 3y² + 4y – 7
(b) 3y² – 4y – 7
(c) 3y² + 4y + 7
(d) 2y² + 4y – 7
- Ravi’s age is twice his sister’s age minus 4 years. If sister’s age is x years, express Ravi’s age.
(a) 2x + 4
(b) 2x – 4
(c) x – 4
(d) 4x – 2
- The sum of two odd numbers is always:
(a) Odd
(b) Prime
(c) Even
(d) Composite
- Assertion (A): An exterior angle of a triangle is equal to the sum of its two interior opposite angles.
Reason (R): The sum of angles of a triangle is 180°.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true and R is false
(d) A is false and R is true
SECTION – B
II. Answer the following:
- Simplify:
(i) 15 × 4 – 10 + 6
(ii) 5a – (3a – 2b) – b
- Three friends contribute money represented by algebraic expressions:
A’s contribution: 3(2p + q – 4r) – (p – 2q + r)
B’s contribution: 2(p – 3q + 2r) + 4q
C’s contribution: 5(p + q – r) – 3(2p – q + r)
a) Find the total contribution.
b) If the target amount is (12p + 5q – 6r), check whether their contribution is sufficient. If not, find how much more is required.
- The perimeter of a triangle with sides (3x + 2), (2x – 1), and (x + 5) is equal to the perimeter of a rectangle with length (2x + 4) and width (x + 2).
Find the value of x.
- In an isosceles triangle, the vertex angle is 120°.
Find the measure of each base angle and all angles of the triangle.
- Construct a triangle ABC using ASA criteria with the following measurements. Also write the steps of construction.
AB = 7 cm
∠ ABC = 60°
∠ BAC = 50°
SECTION – C
III. CASE STUDY
- Mohan collected three sticks of lengths 4 cm, 5 cm, and 11 cm to form a triangle.
(a) Can he form a triangle? Why?
(b) State the triangle inequality property.
(c) Check whether sticks of lengths 6 cm, 8 cm, and 10 cm can form a triangle. Justify your answer.
📘 ANSWER KEY – SET 2
Subject: Mathematics
SECTION – A
1.
Two sides = 12 cm and 8 cm
For triangle:
|12 − 8| < third side < 12 + 8
4 < third side < 20
21 cm is not possible.
✅ Correct Answer: (c) 21 cm
2.
Twin primes whose sum is 18 → 5 and 7 (sum 12 ❌), 11 and 13 (sum 24 ❌)
No twin primes add up to 18.
❗ No correct option (Question data inconsistent)
3.
Required expression =
(7y² + y – 5) – (4y² – 3y + 2)
= 3y² + 4y – 7
✅ Correct Answer: (a) 3y² + 4y – 7
4.
Ravi’s age = 2x – 4
✅ Correct Answer: (b) 2x – 4
5.
Odd + Odd = Even
✅ Correct Answer: (c) Even
6.
Both statements are true and Reason explains Assertion.
✅ Correct Answer: (a)
SECTION – B
7. Simplify
(i)
15 × 4 – 10 + 6
= 60 – 10 + 6
= 56
(ii)
5a – (3a – 2b) – b
= 5a – 3a + 2b – b
= 2a + b
✅ Answers:
(i) 56
(ii) 2a + b
8. Contributions
A = 3(2p + q – 4r) – (p – 2q + r)
= 6p + 3q – 12r – p + 2q – r
= 5p + 5q – 13r
B = 2(p – 3q + 2r) + 4q
= 2p – 6q + 4r + 4q
= 2p – 2q + 4r
C = 5(p + q – r) – 3(2p – q + r)
= 5p + 5q – 5r – 6p + 3q – 3r
= –p + 8q – 8r
Total Contribution:
(5p + 5q – 13r)
- (2p – 2q + 4r)
- (–p + 8q – 8r)
= 6p + 11q – 17r
Target = 12p + 5q – 6r
Difference =
(12p + 5q – 6r) – (6p + 11q – 17r)
= 6p – 6q + 11r
❌ Not sufficient
They need 6p – 6q + 11r more
9. Perimeter Equality
Triangle perimeter:
(3x + 2) + (2x – 1) + (x + 5)
= 6x + 6
Rectangle perimeter:
2(2x + 4 + x + 2)
= 2(3x + 6)
= 6x + 12
Equating:
6x + 6 = 6x + 12
6 = 12 ❌
❗ No solution (Question inconsistent)
10.
Vertex angle = 120°
Remaining angles = 180 – 120 = 60°
Each base angle = 60 ÷ 2 = 30°
✅ Angles are:
30°, 30°, 120°
11. Construction Steps (ASA)
- Draw AB = 7 cm
- At B construct angle 60°
- At A construct angle 50°
- Extend rays to meet at C
- Join AC and BC
Triangle ABC constructed.
SECTION – C
12. Case Study
(a) 4 + 5 = 9 < 11
Triangle cannot be formed.
(b) Triangle Inequality Property:
Sum of any two sides of a triangle must be greater than the third side.
(c) Check 6, 8, 10
6 + 8 = 14 > 10
8 + 10 = 18 > 6
6 + 10 = 16 > 8
✅ Triangle can be formed.
