✨ 12 New Questions on Algebraic Expressions
Easy Level (1–4)
Q1. A notebook costs ₹m and a folder costs ₹n. Write an expression for the cost of 3 notebooks and 2 folders.
Q2. A bottle contains x litres of water. If 3 litres are added, what is the new quantity?
Q3. A taxi charges a fixed rate of ₹50 plus ₹r per km. Write the expression for a ride of 10 km.
Q4. The length of a rectangle is (l + 5) and the breadth is b. Write the expression for its perimeter.
Medium Level (5–8)
Q5. A fruit seller sells apples at ₹8 each and bananas at ₹3 each. Write an expression for the cost of p apples and q bananas.
Q6. A box contains (4k + 3) red balls and (2k – 1) blue balls. Write the expression for the total number of balls.
Q7. A toy costs ₹t. If 5 toys are bought and a discount of ₹20 is applied, write the expression for the total bill.
Q8. A subscription service charges ₹s per month and a one-time joining fee of ₹300. Write an expression for 12 months.
Higher Level (9–12)
Q9. A shopkeeper increases the price of an item costing ₹x by 15%. Write the new price.
Q10. A pipe fills a tank in (a + 3) minutes, but a second pipe empties it in (a – 1) minutes. Write an expression for the net time taken (in fraction form).
Q11. Write and simplify the expression:
(4p+3q)–(2p–q)+5
Q12. A journey consists of 2 parts: the first part covers (3d + 5) km and the second part covers (2d – 1) km. Write an expression for the total distance.
✅ ANSWER KEY — Algebraic Expressions (12 Questions)
Easy Level (1–4)
Q1. Expression for 3 notebooks and 2 folders
Total Cost=3m+2n
Q2. New quantity of water
x+3
Q3. Taxi fare for 10 km
50+10r
Q4. Perimeter of rectangle
Length = l+5, Breadth = bPerimeter=2[(l+5)+b]=2(l+b+5)
Medium Level (5–8)
Q5. Cost of apples and bananas
8p+3q
Q6. Total number of balls
(4k+3)+(2k−1)=6k+2
Q7. Total bill after discount
5t−20
Q8. Subscription cost for 12 months
12s+300
Higher Level (9–12)
Q9. New price after 15% increase
Increase = 0.15xNew Price=x+0.15x=1.15x
Q10. Net time expression (fraction form)
Filling time = a+3
Emptying time = a−1
Net time (difference between rates):Net Rate=a+31−a−11
Q11. Simplify (4p+3q)−(2p−q)+5(4p + 3q) – (2p – q) + 5(4p+3q)−(2p−q)+5
Expand:4p+3q−2p+q+5
Combine like terms:(4p−2p)+(3q+q)+5=2p+4q+5
Final Answer:2p+4q+5
Q12. Total distance
(3d+5)+(2d−1)=5d+4
